中间还有冒号之类的。
直接亮观点吧：
#include<bits/stdc++.h>
using namespace std;
int main(){
long long a,b,c,x,y,z,t;
char m;
long long n=0; cin>>a>>m>>b>>m>>c>>x>>m>>y>>m>>z>>t;
n=(x-a)*3600*t+(y-b)*60*t+(z-c)*t;
cout<<n;
return 0；
}
by fmt931200363 @ 2018-12-15 13:56:49
```c
#include<stdio.h>
int main()
{
long long a,b,c,a1,b1,c1,x,t,s;
scanf("%lld%lld%lld",&a,&b,&c);
scanf("%lld%lld%lld",&a1,&b1,&c1);
scanf("%d",&x);
t=(a1*3600+b1*60+c1)-(a*3600+b*60+c);
s=x*t;
printf("%lld",s);
}
```
//输入之间没有“ ： ”
c++代码（本人是学c++的):
```cpp
#include <iostream>
int main()
{
long long a,b,c,a1,b1,c1,x,t,s;
cin>>a>>b>>c>>a1>>a2>>a3>>x
t=(a1*3600+b1*60+c1)-(a*3600+b*60+c);
s=x*t;
cout<<s<<endl;
return 0;
}
```
by RuSun @ 2019-02-22 11:09:21
还有using namespace std;
by RuSun @ 2019-02-22 11:10:19
```cpp
#include <iostream>
using namespace std;
int main()
{
long long a,b,c,a1,b1,c1,x,t,s;
cin>>a>>b>>c>>a1>>b2>>c3>>x
t=(a1*3600+b1*60+c1)-(a*3600+b*60+c);
s=x*t;
cout<<s<<endl;
return 0;
}
```
by RuSun @ 2019-02-22 11:11:26
```cpp
#include "cstdio"
int main(){
long long a1,a2,a3,b1,b2,b3,n,s1,s2;
scanf ("%lld%*c%lld%*c%lld",&a1,&a2,&a3);
scanf ("%lld%*c%lld%*c%lld",&b1,&b2,&b3);
scanf ("%lld",&n);
s1=a1*3600+a2*60+a3;
s2=b1*3600+b2*60+b3;
printf ("%lld",(s2-s1)*n);
return 0;
}
```
by 大犇≠大奔 @ 2019-10-31 08:33:02
@[妄想之埋](/user/154567) 第三个scanf少了个ll
by 妄想之埋 @ 2020-05-16 08:54:55