除法记得强制转化为整形

P1449 后缀表达式

#早上刚AC了此题,直接全部都是int型即可 AC代码:(抄袭?变棕吧!) ```cpp #include<bits/stdc++.h> using namespace std; int a[1000],*top; char s[1000]; void push(int x) { *top=*top+1; a[*top]=x; } void pop() { a[*top]=0; *top=*top-1; } int main() { top=&a[0]; scanf("%s",s); int i=0,r=1,j,ans,y,z; while(i<strlen(s)) { if (s[i]=='.') { ans=0; r=1; j=i-1; while(s[j]>='0'&&s[j]<='9'&&j>=0) { ans=ans+r*(s[j]-'0'); r=r*10; j=j-1; } push(ans); } if (s[i]=='@') { cout<<a[1]<<endl; return 0; } if (s[i]=='+') { y=a[*top]; z=a[*top-1]; pop(); pop(); push(y+z); } if (s[i]=='-') { y=a[*top]; z=a[*top-1]; pop(); pop(); push(z-y); } if (s[i]=='*') { y=a[*top]; z=a[*top-1]; pop(); pop(); push(y*z); } if (s[i]=='/') { y=a[*top]; z=a[*top-1]; pop(); pop(); push(z/y); } i=i+1; } } ```
by Luban @ 2019-01-21 17:47:46


数据都是整型吗?
by difficult @ 2019-05-19 11:19:50


@[Light_Of_Wisdom](/user/113600) tlqtj 烤谷*3
by y_kx_b @ 2022-08-22 11:34:44


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